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Chemistry Solutions

$250-750 USD

Closed
Posted over 6 years ago

$250-750 USD

Paid on delivery
I need someone to create solutions to 60 multiple chemistry questions I have. I will provide answer key. Solutions must explain to the student how the answer was arrived step by step and MUST be clear with proper grammer. I will pay really well. If you are interested, please provide me the solution to this question in a word document: Assuming no heat is lost to the surrounding, what is the final temperature when 100.0 mL of water at 90.0 °C is added to 200.0 mL of water at 10.0 °C?
Project ID: 15509357

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51 freelancers are bidding on average $347 USD for this job
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Hello, I can work on the chemistry questions and deliver accurate answers. Relevant Skills and Experience Chemistry, science, calculations Proposed Milestones $263 USD - negotiate the price and work on the whole paper
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Hi i am PhD in chemistry. I have 7 years of research and writing experience and have worked on PhD level thesis projects, published papers in peer reviewed journals and have also worked with several companies on creating research based reports and formulating novel products. I have excellent academic writing skills and statistical analysis skills in R , spss, excel to complete any assignment in high quality. Looking forward to discussion, Best Regards, Suyash
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4.7 (160 reviews)
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100 * (90-x) = 200* (x-10) or 450-5x = x-10 or x = 73.33 Relevant Skills and Experience Temperature of mixture would be 73.33 deg C Proposed Milestones $250 USD - completion Please ping me. Thanks.
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4.9 (86 reviews)
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check profile Relevant Skills and Experience check profile Proposed Milestones $250 USD - check profile check profile
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4.7 (105 reviews)
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I graduated from IIT kharagpur , India in 2016 and am currently doing my PhD in applied maths. Relevant Skills and Experience The solution of the sample question will be based on the thermal capacity of water. Proposed Milestones $555 USD - completion
$555 USD in 10 days
4.9 (90 reviews)
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I can definitely help you with your project. Wich my many years of experience teaching mathematics and science and my knowledge of chemistry. I will provide you with top original solutions. Relevant Skills and Experience Chemistry, Mathematics, Science Proposed Milestones $351 USD - Milestone 1 Here, after the mixing, the colder water will warm up while the warmer water will cool down and the mixture will end up with the same temperature. Let the final temperature be x. The change in temperature (dt) as the colder water warm up is given by dt = x - 10 and the change in temperature (dt) as the warmer water cools down is 90 - x. The amount of heat gained by the cooler water is equal to the amount of heat lossed by the warmer water. Qlost = Qgain The amount of heat (Q) is given by mass times change in temperature times specific heat capacity (Q = m x dt x C). The specific heat capacity of water is 4.184 J per kg per K 100(90 - x)(4.184) = 200(x - 10)(4.184) 90 - x = 2x - 20 3x = 110 x = 110 / 3 = 36.67 Therefore, the final temperature is 36.67 degree C. I could not provide a word document because bidding does not support upload of documents.
$351 USD in 10 days
5.0 (36 reviews)
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Hello, My name is Emmanuel. I am a chemical engineer. I understand you are currently for an expert to explain in steps and simple terms the solution to various chemistry problems. Relevant Skills and Experience I can deliver your project. I have skills on Microsoft word. Kindly check my profile and contact me for further information. I have the sample solution ready in Microsoft word file. ANS: 36.67. Proposed Milestones $300 USD - Completion SOLUTION STEP 1. Let the final temperature (temperature that both water will attain after being mixed) be ‘x’. From the temperature gradient, the gradient for the hot side becomes 90-x and for the cold side x-10. STEP 2. Convert the volume of water to mass of water using the density of water. The density of water is 1g/ml mass of water=Density×volume of water Mass of hot water becomes: m_hot=100 mL×1g/ml m_hot=100g Mass of cold water becomes: m_cold=200 mL×1g/ml m_cold=200g STEP 3. Using the formula for energy equation q=mC_p ΔT Where Cp is the heat capacity constant with a value of 4.184 J/goC. Therefore, q_hot=q_cold 100 g×4.184 J/(g℃)×(90-x)=200 g×4.184 J/(g℃)×(x-10) 418.4 J/℃×(90-x)=836.8 J/℃×(x-10) 37656-418.4x=836.8x-8368 37656+8368=836.8x+418.4x 1255.2x=46024 x=46024/1255.2 x=36.67℃
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Here the mixture will come to a equilibrium temperature after cold water extracts heat from hot water. take density and specific heat of water as 1kg/ltr and 4000 J/K kg respectively. Q=mcdT = pvcdt Relevant Skills and Experience Heat taken from c.w = Heat lost from h.w 1*.2 l *4000*(t-10) = 1*.1 l *4000*(90-t) t = 36.7 c Proposed Milestones $600 USD - full
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Am smart in chemistry and 24/7 available. Within a span of 2 days, I can accomplish it completely. Hire my please.. You won't regret it. Thanks
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$300, 10 days Relevant Skills and Experience Biology, Chemical Engineering, Mathematics, Physics, Research Writing Proposed Milestones $300 USD - All the question solutions I have done the sample question but I don't see the provision for upload. Message me and I'll upload it from there.
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Hi Dear ! I am seeing your project and i thought i am the most specific and suitable person for it. Your Project is simply related to my interest. I have the best reviews in this skill. Relevant Skills and Experience I will complete your project on given time surely. Your satisfaction will be my first priority. Stay tuned, I'm still working on this proposal.
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HI, I AM expert in chemistry Relevant Skills and Experience please award me this project thanks Proposed Milestones $555 USD - all solutions
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just sending task Relevant Skills and Experience Physic, data scientist Proposed Milestones $300USD - ok u
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I am studying at Indian Institute of Science Education and Research, Kerala, India. I am pursuing my BS-MS dual degree and with Chemistry as my major subject and Biology as my minor. Relevant Skills and Experience I know topics like Chemical Thermodynamics, Mole concept, Chemical and Ionic Equilibrium, Organic Chemistry, Inorganic Chemistry and Physical Chemistry. Proposed Milestones $250 USD - No Milestones Yet I am a merit rank holder in the IIT-JEE exam which has Chemistry as one of the most important subjects.
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Hi , I am an experienced chemical engineer with excellent chemistry knowledge , and I have done lots of these kinds of work before. Contact me if you are interested and you will get the best work Relevant Skills and Experience Physical Chemistry, Inorganics and Organics, thermal chemistry , chemical engineering Proposed Milestones $250 USD - whole project
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5.0 (17 reviews)
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Hello. the result of this problem is 110/3. I can sure about my price and the deadline. Relevant Skills and Experience Math,Chemistry Proposed Milestones $555 USD - Discuss
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I have teaching skill for eight years experience in chemistry and biology. Conducting my own Institute for international ordinary level and advance level classes (Cambridge ). Relevant Skills and Experience I have teaching skill for eight years experience in chemistry and biology Proposed Milestones $555.56 USD - Hand over the document with full explanations I will send the solution when you contact with me. Please send me a message to send the solution word document.
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multiple chemistry questions with detailed. Relevant Skills and Experience i am graduated from faculty of science ,chemistry department Proposed Milestones $555 USD - in 10 days Q1 = heat lost by liquid 1 Q2 = heat gained by liquid 2 Q = mc(delta T) Q1 = Q2 m1c1 (Thot - Teq) = m2c2 (Teq - Tcold) Specific heat (c) is the same for both since they're both water so you can remove it from the equations. So: m1(Thot-Teq) = m2(Teq - Tcold) in water 1 ml=1gm 100g(90C - Teq) = 200g(Teq - 10C) 9000g-C - 100gTeq = 200gTeq 2000g-C 11000g-C = 300gTeq 11000g-C/300g = Teq 36.66C = Teq
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I can contribute to the project from my professional experience and make the most of that in favor of the achievement of objectives Relevant Skills and Experience I am proactive and delivered 100% to the fulfillment of the objectives of the project. Proposed Milestones $50 USD - Research key concepts $50 USD - Identify key concepts $288 USD - Ask formal questions with their respective solutions
$388 USD in 10 days
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I am a chemical engineer and I am fast at calculations. I have been teaching university students and have an experience to use the right and easy terminology to explain an answer. Relevant Skills and Experience All the mathematical calculations are right at my finger tips. I am fast at calculations and I am fluent in English having written thesis/research papers. Proposed Milestones $130 USD - After successful attempt of 30 questions $147 USD - After completion of entire assignment Additional Services Offered $1 USD - If you find an issue in the assignment, I will work on all the issues until you are satisfied. Notes: 1. The warmer water cools down and the cooler water warms up. Which means the final temperature of the mixture will be same. 2. As there is no phase change, The energy lost (ql) = The energy gained (qg) Let the final temperature be ‘x’ Q=mCp∆T Therefore: mCp∆T = mCp∆T 200 x 4.184 x (90-x) = 100 x 4.184 x (x-10) X=36.6c
$277 USD in 2 days
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Flag of CANADA
windsor, Canada
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