Chemistry Problems

Hello I have seen the attached images and can solve these type of problems. Thanks........................

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hi i completed my PhD in chemistry.i am expert in chemistry. i can help you with 100% accuracy within your time limit. please contact me I gone through all your questions. I can solve all the questions. I will deliver answers after 2 hours of bid granting. thank you.

Hi, I am a Mechanical Engineer with a first class honors degree. I can provide the answers for your chemistry problems accurately within the time you specify. You can check the reviews I got for my recent chemistry project and other projects to get an understanding of the quality of work that I maintain. Let me know the project particulars so that I can start working on it without further delay. Regards

give me 24 hours i will do it until finish and how much you paid me?? if you agree with me please send personal message

Hi there, I can solve the problems. contact me for hire this project. I am looking forward four your reply

I am petrochemical engineer so this is very simple. I can solve for you! I am very confident with your project. If you agree, please send me an email to duccanh179@ gmail.com. I will give you solve after 1 day

I'll do the task with brief explanations. Now Exam1 is already (1-19 tasks). For sample: 1. ... Al(CH3COO)3 M(Al) + (M(C)*2+M(O)*2+M(H)*3)*3 26.98 + (12.01*2 + 16.00*2+3*1.01)*3 = 204.13 answer: E. _______________________________________________________ 12. ... 1 O2 + 2 H2 P(O)+ P(H) = P 1/2P(O) = P(H) = Px 1/2Px + Px = P Px = P/1.5 = 741/1.5 = 494 mmHg (torr) answer: E. ___________________________________________________________ 18. ... all atoms O on right = all at. O on left for other atoms - too (N(P)left = N(P) Right for sample) => 2*P = 2*P; 3*Cl (FeCl3) = 3Cl (3NH4Cl) 3*NH4OH + 1*FeCl3 = 3NH4Cl + 1*Fe(OH)3 3*Na2CO3 + 2*H3PO4 = 2*Na3PO4 + 3*H2O + 3*CO2 2*C2H6 + 7*O2 = 4*CO2 + 6*H2O _______________________________________________________ If need other format (no txt -> doc/docx/pdf e.t.c) - I'll do it.